Here is a way to do it using two hashes, %n_count to keep track of the number of times each name appears, and %f_count to keep track of the files in which each occurs.
my (%f_count,%n_count); for my $file (@files) { open( my $fh, '<', $file ) or die "Couldn't read '$file': $!"; while (my $line = <$fh>) { chomp $line; next unless $line; my ($name,$number) = split(',',$line); $n_count{$name}++; $f_count{$name}{$file}++; } }
Then you need to extract the names - first get the names that appear at least 25 times in the %n_count hash, then, for each of those candidate names, get the ones that appear in all files.
my $num_of_files = scalar @files; my $min = 25; my @candidates = grep { $n_count{$_} >= $min } keys %n_count; for my $name (@candidates) { my $in_files = scalar keys %{ $f_count{$name} }; next unless $in_files == $num_of_files; print "$name\n"; }
The only tricky bit here is the scalar keys %{ $f_count{$name} }
$f_count{$name} is a hash reference, where each key is a file name. We can get at the keys by dereferencing the hash %{...} and counting how many there are. If that count equals the number of files then that name is in every file.

In reply to Re: Extracting common keys present in multiple files by tangent
in thread Extracting common keys present in multiple files by Anonymous Monk

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