Presumably, because his data does not represent some quantity to approximate normal distribution.

Transforming the D with f = 1 / x yields:
Row Value Z Significant Outlier?
1 10.000000000000000000 1.78885438120805620000 Significant outlier. P < 0.05
2 0.000666666666666667 0.44717876261411860000  
3 0.000588235294117647 0.44719630129821775000  
4 0.000476190476190476 0.44722135656121640000  
5 0.000312500000000000 0.44725796073450363000  

Transforming the D with f = log x gives:
Row Value Z Significant Outlier?
1 -2.30258509299405 1.7851028840345886 Significant outlier. P < 0.05
2 7.31322038709030 0.3777123990128823  
3 7.43838353004431 0.4058644616784443  
4 7.64969262371151 0.4533927252416877  
5 8.07090608878782 0.5481332981015742  


In reply to Re^2: How to best eliminate values in a list that are outliers by Anonymous Monk
in thread How to best eliminate values in a list that are outliers by Anonymous Monk

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