TIMTOWTDI

personally I much prefer hippos approach with lexical sorting!

FWIW here a solution with a regex searching through a concatenation of all strings for the longest repeated pattern:

use strict;
use warnings;


my @strings = (
    'string that I need to gather the common base from: number 1 and s
+ome other junk in it',
    'string that I need to gather the common base from: number 2 and s
+ome other junk in it',
    'string that I need to gather the common base from: number 3 and s
+ome other junk in it',
);

my $sep   = "\0";
my $nosep = "[^$sep]";
my $all   = join $sep, @strings;


$all =~ /^ ($nosep*) $nosep*? ( $sep \1 $nosep*? )+ $/x;

print "solution: '$1'";

[download]

OUTPUT:

solution: 'string that I need to gather the common base from: number '

Please note that you need to take care that the separator (here \0 ) is not part of any string.

You could easily check by counting $sep in $all.

Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
Je suis Charlie!

In reply to Re: An efficient way to gather a common portion of several strings' beginnings by LanX
in thread An efficient way to gather a common portion of several strings' beginnings by igoryonya

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