To make a regexp faster, search from start or end, using ^ or $ to bind it to that point. But can you explain what you want to do? I am sure there is a better way.

As for code, look at the multiplier x 3 that concatenates the string 3 times. Then, we use qr to quote a regular expression, which we then use and capture the results in @R, which we then print. Hope this gets you ideas. (duplicating the expression to capture it 2 times) 

$ perl -e '$s="(\\d\\w)" x 3; $X="a1b2c3d4e5"; $m=qr/$s/; @R=$X=~$m;  
+print join(";",@R)."\n"' 
1b;2c;3d

[download]

another way could be divide and conquer. Paying a penalty by using $' (the rest of the string that has not matched yet) for the next iteration. another idea is using index

In reply to Re^3: How to match more than 32766 times in regex? by FreeBeerReekingMonk
in thread How to match more than 32766 times in regex? by rsFalse

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