1. I can't understand how your first regex can match more than 32677 times agains string '0' x 1_000_000 ? And it gives correct answer 3. It has a '+' quantifier, which is {1,32677}, true?
Its an optimization. (0)+ is equivalent to 0{1,23677}, 0+ is not. There are many places where Perl's regexes engine doesn't behave like a straighforward backtracking engine - specifically to fix problems inherent to backtracking regex engines. The restriction on the depth of recursion is one of these places too.

You can see what the regexes compile into with:

$ perl -Mre=debug -e 'qr/0+|1+/;
Final program:
   1: BRANCH (5)
   2:   PLUS (9)
   3:     EXACT <0> (0)
   5: BRANCH (FAIL)
   6:   PLUS (9)
   7:     EXACT <1> (0)
   9: END (0)
minlen 1

[download]
compare: 
 $ perl -Mre=debug -e 'qr/(0)+|(1)+/'
Compiling REx "(0)+|(1)+"
Final program:
   1: BRANCH (12)
   2:   CURLYN[1] {1,32767} (23)
   4:     NOTHING (6)
   6:     EXACT <0> (0)
  10:   WHILEM (0)
  11:   NOTHING (23)
  12: BRANCH (FAIL)
  13:   CURLYN[2] {1,32767} (23)
  15:     NOTHING (17)
  17:     EXACT <1> (0)
  21:   WHILEM (0)
  22:   NOTHING (23)
  23: END (0)
minlen 1 
Freeing REx: "(0)+|(1)+"

[download]
Your solution doesn't cope with inputs
This entire approach - using regexes for this problem - is nonsense, and the way you write code doesn't help at all.

In reply to Re^9: How to match more than 32766 times in regex? by Anonymous Monk
in thread How to match more than 32766 times in regex? by rsFalse

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