But now say if third value that is generated is 80 . At this point in time $root still points to the orignal tree with value 40. Now because $root is already defined it skips to the if else condition , and makes a call that 80 > 40 , hence it should be inserted to the right But $tree->{Right} is already defined , and it contains the value 60, so it never executes the actual routine to create a reference to a new tree
Yes, $tree->{Right} is already defined, so it recurses again, and inserts 80 as the right son of 60. 
($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord
}map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,

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In reply to Re^3: How do I create a binary tree ? by choroba
in thread How do I create a binary tree ? by punitpawar

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