Monks - I have a text file that I'm trying to open, and reformat each line. The file contents looks like this: 
1996.40637
1996.41064
1996.41199
1996.41467
1996.41882

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I want to write a regex that takes one of these dates, removes the decimal, and removes the first two #'s, i.e. from 1996.41064 to 9641064 I can get the pattern right, but not the replacement. Can you help fix the statement to 
$new = s/\d+.\d/replacement/g;

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get the replacement string to work? I tried using substr on the value, but this didn't work, i.e. 
$new = s/\.//g;
$new = substr($new, 2);

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Thanks

In reply to substr on $_ by gisrob

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