Non-numeric strings evaluate as zero when used in arithmetic. 

$ perl -lwe 'use strict; print int "NANNY"; print int "non-numeric";'
Argument "NANNY" isn't numeric in int at -e line 1.
nan
Argument "non-numeric" isn't numeric in int at -e line 1.
0
That is to say: perl did not error out in seek() because the seek to zero offset was successful.

What is the reason for passing non-numeric offset? You will have to check the passed value yourself, or, better yet, fix the program logic to not pass a string where a number is expected!

In reply to Re: perl not going to error path by Anonymous Monk
in thread perl not going to error path by gupr1980

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