Hi

In Boolean function evaluations using Perl, what is the difference between these two expressions:

#1 Y = (A & B)
#2 Y = (A * B)

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I cannot seem to find documentation on the #2 form of expression, even though I have seen #2 in Boolean expressions used in Perl. For example, this thread has #2 style: parser for evaluating arbitrarily complex boolean function in a string

Bill Murphy

In reply to Boolean operation: (A & B) vs (A * B) by Anonymous Monk

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