well it's a bit more complicated... 1+1 = 2, see my post Re: Boolean operation: (A & B) vs (A * B)
as pointed out neither the OP nor hippo used +, I saw the wider scope ...
Cheers Rolf
(addicted to the Perl Programming Language and ☆☆☆☆ :)
Je suis Charlie!
In reply to Re^2: Boolean operation: (A & B) vs (A * B)
by LanX
in thread Boolean operation: (A & B) vs (A * B)
by Anonymous Monk
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