So, I understand this is true. I'm O.K. with overflows. I can handle overflows. But why does 
$var = time * 1000;

[download]
overflow and 
 
$var = time; $var *= 1000;

[download]
not overflow?

I believe that on my system (Win2k, perl 5.6.1) integers are 32 bit, just like returned by time() I verified this with print ($var&(~0)) which gives me (2**32)-1.

Does perl automatically decide (not) to use BigInts? Any ideas?

Ira,

"So... What do all these little arrows mean?"
~unknown

In reply to Re: Re: time() function by IraTarball
in thread time() function by Anonymous Monk

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