Hello. I tried to avoid some parenthesis and have got some problems.
Firstly, I wanted to write this code in fashion of ternary operator:
perl -le '$_ = "a"; print do { if( length ){ "A" } else{ "B" } };'
OUTPUT:
A
There is with "ternary":
perl -le '$_ = "a"; print length ? "A" : "B" '
OUTPUT:
Warning: Use of "length" without parentheses is ambiguous at -e line 1 +. Use of ?PATTERN? without explicit operator is deprecated at -e line 1. Search pattern not terminated or ternary operator parsed as search pat +tern at -e line 1.
I forgot that 'length' is unary operator with higher precedence, so it interpret following '?' as matching parens. Same if I would write: 'print length // "A" ' - error, when 'print length || "A" ' - is ok.
So I tried to avoid 'length' to interpret '?' as regex in this way:
perl -le '$_ = "a"; print length . '' ? "A" : "B" '
But it still outputs:
Use of ?PATTERN? without explicit operator is deprecated at -e line 1. Search pattern not terminated or ternary operator parsed as search pat +tern at -e line 1.
Concatenation point has higher precedence than unary 'length' so I think 'length' should give its value which will be concatenated with empty line, and later ternaty op., and later - 'print'.
If I use '+ 0' instead, I got warning of ambiguity (but '+' can't start a regex, and for me seems that there is no ambiguity):
perl -le '$_ = "a"; print length + 0 ? "A" : "B" '
Warning: Use of "length" without parentheses is ambiguous at -e line 1 +. A

In reply to parsing 'length ...' by rsFalse

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