In your example code, Perl is seeing sub_B as the parameter to sub_A. Since the sub declarations came before the calls, parens are not needed as compiler clues, so it's perfectly legitimate syntax. Almost exactly the same as sub_A(sub_B()).

So for sub_A to be called, sub_B must first be called so that its return value can be passed as the parameter to sub_A.


Dave

In reply to Re: sub execution order aka missing semicolon after sub call by davido
in thread sub execution order aka missing semicolon after sub call by jmaas

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