PassRegex($str =~ /b/i, 'parm2', 'parm3');
I believe that regex is evaluated in list context, not scalar context. In that case, the m operator returns an empty list when there is no match. From perlop: 
an empty list is returned upon failure.

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An empty list is a list with no items. So, when there is no match, you actually pass a list of 2 items to your sub, not 3. You could use this to force scalar context: 
PassRegex(0+($str =~ /x/i), 'parm2', 'parm3');

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Or, be more explicit with: 
PassRegex($str =~ /x/i ? 1 : 0, 'parm2', 'parm3');

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In reply to Re: Passing regex result into function by toolic
in thread Passing regex result into function by sdsommer

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