This is a DB question rather than a Perl one. Here's the answer:
SELECT id FROM lockers AS l WHERE NOT EXISTS = (SELECT 1 FROM units AS u WHERE u.locker = l.id)

And here's a full demonstration:

#!/usr/bin/perl use warnings; use strict; use DBI; use List::Util qw{ shuffle }; my $dbfile = '1.db'; my $dbh = 'DBI'->connect('dbi:SQLite:dbname=' . $dbfile, q(), q()); $dbh->do('CREATE TABLE lockers (id INT)'); $dbh->do( << '__SQL__' ); CREATE TABLE units (id VARCHAR, locker INT, FOREIGN KEY(locker) REFERENCES lockers(id)) __SQL__ my $insert_locker = $dbh->prepare('INSERT INTO lockers (id) VALUES (?) +'); $insert_locker->execute($_) for 1 .. 25; my @ids = map "u$_", 1 .. 80; my $insert_unit = $dbh->prepare('INSERT INTO units (id, locker) VALUES + (?, ?)'); $insert_unit->execute($_, undef) for @ids; my $add_locker = $dbh->prepare('UPDATE units SET locker = ? WHERE id = + ?'); my @lockers = shuffle(1 .. 25); my $i = 0; $add_locker->execute($lockers[$i++], $_) for (shuffle(@ids))[1..24]; my $unassigned = $dbh->prepare( << '__SQL__' ); SELECT id FROM lockers AS l WHERE NOT EXISTS (SELECT 1 FROM units AS u WHERE u.locker = l.id) __SQL__ $unassigned->execute; while (my @row = $unassigned->fetchrow_array) { print "Free locker: @row\n"; } unlink $dbfile;

($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord }map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,

In reply to Re: Locate missing number in a series by choroba
in thread Locate missing number in a series by htmanning

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