Hello sargg55,

foreach my $scalar(@array)
{
$total+=scalar;
}

[download]

You’ve named the foreach variable $scalar, but in the loop body you’ve left off the $ sigil. Now, it so happens that scalar is a built-in function in Perl (it puts its argument into scalar context), so the interpreter thinks you’re calling the function — without an argument. Add the sigil:

$total += $scalar;

[download]

and it should compile cleanly. See scalar.

Hope that helps,

Athanasius <°(((>< contra mundum Iustus alius egestas vitae, eros Piratica,

In reply to Re: Update: problem with scalar by Athanasius
in thread Update: problem with scalar by sargg55

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