One interesting, but awkward possibility -- that may never occur, but has to be dealt with in case it does -- is if all three points of a triangle are equal.

Then the plane is flat and 'my angle' could cross it with any orientation. I'd have to look to the triangles adjoining the other two sides of the triangles that adjoin at my boundary to see how the potential flows through this boundary segment. Does your vector math cater to that?

Thinking about it more, if a triangle is flat, then it is either a local peak or trough and the potential will flow around, but not through it.

And that leads to the fact that if any segment on my boundary is formed by a pairs of points with equal height, then the potential will not cross the boundary through that segment at all, but rather will flow through the adjoining triangles, parallel to it; or not at all in the flat triangle case.

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
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In reply to Re^5: Contour mapping? (Thank Dog for anonymonk.) by BrowserUk
in thread Contour mapping? by BrowserUk

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