++stevieb

This is also one of the cases where B::Deparse can help: perl -MO=Deparse -e 'print q{}' yields 

print '';
-e syntax OK

[download]
The print statement is there to avoid the value being in void context and optimized away.

In reply to Re: What does q{} mean? by Eily
in thread What does q{} mean? by Wiggins

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