Dear Anonymous, It's very simple. In every iteration the $a receives the earlier value of $b...that's the trick. Bye the way, u can see my ealier attempt, which had one serious mistake... that can be rewritten to give the desired result. See: 
$a=1;
$b=1;

while($a <=200)
    {$c=$a+$b;
     print("$a\n$b\n$c\n");
    $a=$b+$c;
    $b=$c+$a;
    }

[download]
Thanks.

In reply to Re: Re: Re: Fibonacci numbers(Again) by saiful
in thread Fibonacci numbers by Anonymous Monk

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