Disclaimer: cross-posted at StackOverflow.

In Perl5, I can quickly and easily print out the hex representation of the \r\n Windows-style line ending:

perl -nE '/([\r\n]{1,2})/; print(unpack("H*",$1))' in.txt
0d0a

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update:To create a Windows-ending file on Unix, create a in.txt file with a single line and line ending. Then: perl -ni -e 's/\n/\r\n/g;print' in.txt. (or in vi/vim, create the file and just do :set ff=dos) /update

I have tried many things in Perl6 to do the same thing, but I can't get it to work no matter what I do. Here's my most recent test:

use v6;
use experimental :pack;

my $fn = 'in.txt';

my $fh = open $fn, chomp => False; # I've also tried :bin
for $fh.lines -> $line {
    if $line ~~ /(<[\r\n]>**1..2)/ {
        $0.Str.encode('UTF-8').unpack("H*").say;
    }
}

[download]

Outputs 0a, as do:

/(\n)/
/(\v)/

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First, I don't even know if I'm using unpack() properly. Second, how do I capture both elements (\r\n) of the newline in P6?

In reply to Perl6: Capturing newline in a string by stevieb

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