If any of the doesn't make sense, see sort, perlop, perldata, perlsyn.
use strict; my @list_o_num = qw( 1 22 44 55 63 2 1 2 4 54 8 7 9 2 9 ); my @sorted_list_o_num = sort { $b <=> $a } @list_o_num; my( $num_1, $num_2, $num_3 ) = @sorted_list_o_num;
This however, does not account for duplicates (9 9 7), so this approach might be better
#!/usr/bin/perl -w use strict; my @list_o_num = qw( 9 9 9 10 9 8 7 9 6 ); my %list_o_num = map { if ( exists $list_o_num{$_} ) { $list_o_num{$_}++; } else { $_ => 1; } } @list_o_num; my @true_top_3 = sort { $b <=> $a } keys %list_o_num;
None of this is tested, but it should work (short of any typos).

Note: See blakem's comment and example here for a fix to make this solution actually work.


In reply to Re: How to find the N largest values in an array? by Anonymous Monk
in thread How to find the N largest values in an array? by dubx56

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