If your debugger is incompatible with the 'each' magic, then the options are: use a different debugger, or don't use each.

A simple way to work around each would be to load it into an array and simulate each as follows: 

$ perl -e '
> my %h=(qw(a b c d e f));
> { my @each = %h;
>   while (my $k = shift @each) {
>     my $v = shift @each;
>     print "$k => $v\n";
> }}' 
c => d
e => f
a => b

[download]
Update: you could also create an oo version of each that uses a handler object instead of magic so that it can't break under your circumstances. e.g. 
package OOEach;

sub new {
    my ($class) = @_;
    return bless {}, $class;
}

sub each {
    my $self = shift;
    $self->{queue} ||= [@_]; # note: will only init once
    my $k = shift @{$self->{queue}};
    my $v = shift @{$self->{queue}};
    return ($k, $v);
}
;

[download]

One world, one people

In reply to Re: Peek a hash without breaking iterator by anonymized user 468275
in thread Peek a hash without breaking iterator by hurricup

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