If you are trying to pass a reference to some value in a hash to a sub, that is possible. That way the sub wouldn't know the key name. More usual would be to pass a ref to the whole hash and the sub does know the key name. Here is a demo of both possibilities. Hope that I'm not confusing the issue.
#!/usr/bin/perl use strict; use warnings; use Data::Dump qw(pp); $!=1; my %hash; $hash{id1} = 001; $hash{id2} = 002; print "initial hash: ", pp (\%hash), "\n"; my $hash_ref = \%hash; my $ref = \$hash{id2}; # A reference to id2 $$ref = 003; #use ref to a scalar (value of id2) print "modified hash: ", pp (\%hash), "\n"; modify_anon_hash_value ($ref); print "mod by sub : ", pp (\%hash), "\n"; more_normal_way($hash_ref); print "mod more usual: ", pp ($hash_ref), "\n"; sub modify_anon_hash_value #sub doesn't know which { #key's value that it is my $ref = shift; #modifying $$ref = 5; } sub more_normal_way #usual pass the entire hash as ref { my $href = shift; $href->{id2}=8; #sub know which key to use } __END__ initial hash: { id1 => 1, id2 => 2 } modified hash: { id1 => 1, id2 => 3 } mod by sub : { id1 => 1, id2 => 5 } mod more usual: { id1 => 1, id2 => 8 }

In reply to Re: Sub hash param by reference by Marshall
in thread Sub hash param by reference by hankcoder

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