Thank you Marshall, my $ref = \$hash{id2} is exactly what I am trying to look for.

Your given example is perfect. I'm just curious, when calling sub modify_anon_hash_value ($ref) is it possible to do it like modify_anon_hash_value (\$hash{id2}) ? without need to do my $ref = \$hash{id2}.

I have test run it with 

modify_anon_hash_value (\$hash{id2});

[download]
The result return correctly without any error. Just to confirm if this way of coding is allowed or it may be a bad way to do it.

In reply to Re^2: Sub hash param by reference by hankcoder
in thread Sub hash param by reference by hankcoder

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