You are creating a NEW button ID each time through the loop.

Your print should be something like: 

print "<input type=image name='$unit_name' id='unit_name' value='$unit
+_name' alt=airConButton src=../../images/unit.jpg height=100px width=
+100px onclick=this.form.submit()>";

[download]
Now, the "submitted" page will receive 
param('unit-name')

[download]
although, if you have multiple buttons with the same id (unit_name), you may get an array of values.

UPDATE:You should get the value of the button used to submit (Untested).

UPDATE 2Revising unsatisfactory answer.
The trick is to submit a different value for the same Name, via Javascript.
Untested: (You need to CREATE a Hidden form field with the name "unit_name") 

print "<input type='image' name='$unit_name'  alt=airConButton src='..
+/../images/unit.jpg' height='100px' width='100px' 
onclick='document.forms[0].unit_name.value =\"$unit_name\";this.form.s
+ubmit()'>";

[download]

        "Software interprets lawyers as damage, and routes around them" - Larry Wall

In reply to Re^3: Passing perl variable as input name? by NetWallah
in thread Passing perl variable as input name? by RobRobson

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