o.k that last one was a poor example as I could have computed the components first. The solution is required for other logical possibilities, such as:

v1 -> v2

v2 -> v3

v2 -> v5

v3 -> v4

The paths would then be:

v1 -> v2 ->v3 -> v4

v1 -> v2 -> v3

In reply to Re^3: How do I use Graph::Traversal? by Anonymous Monk
in thread How do I use Graph::Traversal? by thor

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