I can reproduce this exact behaviour with this simple script, by trying to link to a non-existent library

I can reproduce the problem with an even simpler script:
use Inline C => 'END'; say(); __END__ __C__ void say() { printf("6\n"); }
The first line of that code is wrong. The corrected version of that script is:
use Inline C; say(); __END__ __C__ void say() { printf("6\n"); }
Update: An alternative way of writing out the script would be:
say(); use Inline C => <<'END'; void say() { printf("6\n"); } END
I think that might have led to your confusion.

Cheers,
Rob

In reply to Re^3: With Inline::C, how to link to external library? (XS) by syphilis
in thread With Inline::C, how to link to external library? by stevieb

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