Marshall,

 

Are you saying that a foreach loop would be just as fast as what Limbic-Region was suggesting for an array? Consider the following solution concept, which is what I had before, that I don't think is nearly so fast (though I didn't time it precisely).

foreach $replace (@substitutionlist) { ($oldline, $newline) = split(/\t/, $replace); $newline = s/\s/_SPACE_/g; #….more code here foreach $line (@array) { $count += s/\b$oldline\b/$spliced/eg for @array; #….more code here } } s/_SPACE_/ /g for @array;

Consider that @substitutionlist has over 10,000 lines, and @array has over 30,000, with many lines requiring multiple substitution replacements on a single line. Is the foreach setup outlined above really just as efficient?


In reply to Re^2: How to count substitutions on an array by Anonymous Monk
in thread How to count substitutions on an array by Anonymous Monk

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