$count = () = s/// is a single expression that repeats for each element in @array. Apparently the final element in @array matches but once. If there were two patterns in the final element of @array matching your pattern, then the could would be 2. On each iteration of your for loop the expression is evaluated against a new $_ input, and $count is replaced. You do not employ an accumulator of any kind.

If you wanted to do this as a single line of code you could do this:

do {$count = () = $s/PATTERN/REPLACEMENT/g; $acc += $count} for @array
+;

[download]

Update: Apparently it's not my day. See below. Thanks AnomalousMonk.

In the end, $acc should contain your total number of matches.

Keep in mind that your /e modifier is probably wrong, and maybe a risk. If the replacement comes from somewhere outside of your control, it could be used to pass a destructive command through the Perl interpreter.


Dave

In reply to Re: How to count substitutions on an array by davido
in thread How to count substitutions on an array by Anonymous Monk

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