A stray random thought when I looked at a use constant usage: 
use constant {continue=>0, next=>1, redo=>2, last=>3 };

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Isn't the stuff in brackets an anonymous hash? Isn't the ordering of hashes strictly not guaranteed by default?

So how could that work, since the numbers and the labels in the hash, it would seem, should end up in a random order?

I know the following would fail (because the RHS of the 'our $clist' won't be done at compile time): 

our $clist = {continue=>0, next=>1, redo=>2, last=>3 };
use constant $clist;

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But how is it that this seems to always work: 
#(Using): alias tperl='perl -we'\''use strict; use P;'
> tperl
our $clist;
use mem($clist = {continue=>0, next=>1, redo=>2, last=>3 });
use constant $clist;
P "redo=%s, last=%s", &redo, &last;'
redo=2, last=3

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Is it that compile-time hashes are not randomized? Never really thought about it before, but I guess they can't be?

In reply to Curious: are anon-hashes in random order? by perl-diddler

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