I want to know if libXSLT in 
Perl -v

This is perl, v5.8.8 built for darwin-thread-multi-2level Copyright 19
+87-2006, Larry Wall....

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on following OSX's build 
uname -a 

Darwin machine-maci 15.3.0 Darwin Kernel Version 15.3.0: Thu Dec 10 18
+:40:58 PST 2015; root:xnu3248.30.4~1/RELEASE_X86_64 x86_64

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not support the exsl extensions at all. Or is it something that I am missing in my OSX's Perl-5.8.8 build which is causing it not support it?
===UPDATE===
1) I have a transformation xsl file which is as follows 
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Tr
+ansform"
    xmlns:xalan="http://xml.apache.org/xslt"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:exsl="http://exslt.org/common"
    extension-element-prefixes="exsl">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="ye
+s" media-type="text/xml"/>
    <xsl:param name="isfile"/>
<xsl:variable name="current-year">
            <xsl:value-of select="date:year()"/>
    </xsl:variable>

    <xsl:template match="/">
         <xsl:when test="$isfile = 'true'"> 
            <exsl:document href = "outputfile1.xml" method="xml" versi
+on="1.0" encoding="UTF-8" indent="yes">                  
                Article:- <xsl:value-of select="/Article/Title"/>
                Authors:- <xsl:apply-templates select="/Article/Author
+s/Author"/>
            </exsl:document>
        </xsl:if>
    </xsl:template>

    <xsl:template match="Author">
        <exsl:document href = "outputfile2.xml" method="xml" version="
+1.0" encoding="UTF-8" indent="yes">                  
            always Generate this output!! <xsl:value-of select="." />
        </exsl:document>
    </xsl:template>
</xsl:stylesheet>

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2) I have an example file which needs to transformed and output needs to generated to output1.xml and output2.xml depending on condition in the xsl file 
<?xml version="1.0"?>
<?xml-stylesheet type="xsl" href="trans.xsl"?>
<Article>
  <Title>My Article</Title>
  <Authors>
    <Author>Mr. Foo</Author>
    <Author>Mr. Bar</Author>
  </Authors>
  <Body>This is my article text.</Body>
</Article>

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3) Here is the perl script that I use for transformation 
#!/usr/local/bin/perl -w

use strict;
use warnings;
use File::Path;
use File::Spec;
use File::Basename;
use XML::LibXSLT;
use XML::LibXML;

my $isfile;

my ($xmlfile,$xsltfile,$samplefile) = qw/ Example.xml trans.xsl sample
+.xml/;

if(-f $samplefile)
{
    $isfile = "true";
    print "File is present\n";
}
else
{
    $isfile = "false";
    print "File is absent\n";
}

my %args = ( "isfile" => $isfile ); 
my $xslt = XML::LibXSLT->new;
my $stylesheet = $xslt->parse_stylesheet_file($xsltfile);
my $results  = 
$stylesheet->transform_file($xmlfile,XML::LibXSLT::xpath_to_string(%{a
+rgs}));
0;

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When the script is ran, I get following error on OS X I get the following error. 
xmlXPathCompOpEval: function year not found
Unregistered function
xmlXPathCompiledEval: evaluation failed
runtime error: file trans.xsl line 24 element value-of
XPath evaluation returned no result.

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However, for the same use case when executed with Perl 5.8.8 on Win7 and Debian 8.3, I am getting no errors. This (usage of outdated Perl in production environment) is something that I can not control and I am still waiting for Perl 5.2x to arrive at my workplace.

In reply to exsl in libXSLT in Perl 5.8.8 on OSX by Recker

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