Good evening

I don't know this one, and don't know if it's possible. I have a long string, let's say $str; I want to substitute all the pattern occurences (supose /\d+/) by one function with the match as argument. So assume, after each match, that the function is: sub add(){($v) = @_;return ($v*4);}

How can I do this?$str =~ s/\d+/&add($1)/gi; doesn't work...and seems terribly wrong...I've placed a simple function, but it can be much more complex.

Regards,

Kepler

EDIT: $str =~ s/\d+/&add($1)/ge; works... :)

In reply to String replace with function by kepler

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