The problem is that you are using the numeric values of the hash in a string context: print $fh "$key $hash{$key}\n";; thus perl converts what were IVs (internal integers) into PVs (internal strings), caching the result in the expectation you might use them in a string context again.

As an IV, each value requires 24 bytes, but once converted to a string and stored in a PV, each value requires ~56 bytes.

You can avoid the conversion being cached by making perl convert a temporary value to a string for printing like this:

printf $fh "$key %d\n", 0+$hash{$key};

That will avoid the memory growth.


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In reply to Re: Devel::Size reports different size after hash access by BrowserUk
in thread Devel::Size reports different size after hash access by Cristoforo

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