It looks like you are printing a reference, rather than the item being "referenced". Try to access the ios_version by de-referencing the variable using:
## print results ## notice the extra "$" in front of the variable print "$error\n$$ios_version\n\n";
The "$$" provides access to the actual data, rather than the reference, which simply "points" to the location of data
In reply to Re: Hash value being called as a Scalar?
by mr_dont
in thread Hash value being called as a Scalar?
by c
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