For some reason, obase variable should be defined first and then ibase

specifically, because you told it to output in base twenty-two.

ibase=16;    # set the input base to hexadecimal.
             # all numerical inputs will be treated with an
             # implied 0x prefix
obase=16;    # 16 is implied hexadecimal 0x16 = sixteen plus six = twe
+nty-two
(A5A5A5A5A5A5A5A5/8);    # divide 0xA5... by 0x8, and output in base t
+wenty-two

[download]

And my copy of the bc manpage explains "For bases 2 through 16, the usual method of writing numbers is used. For bases greater than 16, bc uses a multi-character digit method of printing the numbers where each higher base digit is printed as a base 10 number. The multi-character digits are separated by spaces. ..."

Sanity check: you expected 0x14b4b4b4b4b4b4b4, which is about (0x14) * 16**14, plus some change: 20 * 16**14 = 1.44e18, plus. You got "05 06 01 09 10 06 00 00 05 16 14 07 14 20", which is about 05 * 22**13, plus some change: 1.41e18, plus. Yep, the output was in base-22.

In reply to Re^3: bc within perl by pryrt
in thread bc within perl by amudelkaa

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