But the array value doesn't seem to have the same reference address as the hash value. Are you sure that doesn't make a copy? 
my %hash = ('a'=>'test');
print \$hash{'a'}."\n";
my @arr = delete $hash{'a'};
print \$arr[0]."\n";

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In reply to Re^2: push to array without copying by chris212
in thread push to array without copying by chris212

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