I was working on this from the OP:

"However, when the hash table is empty, we just call return."

That appears to be confirmed in his code example:

... %$hash_ref or return; # just return ... $key; # or last line in sub returns a scalar

So, %some_hash is ending up as one of:

( key1 => ($val1), key2 => ($val2) ) ( key1 => (), key2 => () ) ( key1 => ($val1), key2 => () ) ( key1 => (), key2 => ($val2) )

These will be flattened to:

( 'key1', $val1, 'key2', $val2 ) ( 'key1', 'key2' ) ( 'key1', $val1, 'key2' ) ( 'key1', 'key2', $val2 )

The first is fine; the second is what the OP had a problem with; the last two are problematic but, assuming he's using warnings, should generate an "Odd number of elements in hash assignment" diagnostic (from perldiag).

I don't think the "comma operator returns the right-most value in the list" comes into play in any of these scenarios: all lists are either empty or only have one value.

Am I missing something with your "return (17, 42);" example?

— Ken


In reply to Re^3: Preventing unintended list expansion inside hash literals. by kcott
in thread Preventing unintended list expansion inside hash literals. by gregory-nisbet

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