Instead of the || (or), you need && (and) in your if statement. If I understand you correctly, you want to do the "if" as long as the $username is ok, except if the $type is either of 2 conditions. Edit: I guess in other words, you want to do the "if" if the $username is ok and $type="Something Else";. 
#!usr/bin/perl
use strict;
use warnings;

my $security = "xxx";
my $username = "xxx";
my $type = "Check In";

if ($username eq "$security" and $type ne "Check In" and $type ne "Che
+ck Out" )

{
  print "if executed, username=$username type=$type\n";
}
else
{
  print "if not executed, username=$username type=$type\n";

}
__END__
if not executed, username=xxx type=Check In

*** This is the same thing:***

if (($username eq "$security") and !( $type eq "Check In" or $type eq 
+"Check Out") )

[download]
I show 2 different version of the "if", both do the same thing. This is called DeMorgan's theorem. Note that the "ne" becomes "eq" in the second version. I like the first version better, but your call... they are the same logically.

In reply to Re: And plus OR by Marshall
in thread And plus OR by htmanning

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