No, that is not correct.
STDERR is "unbuffered" by default.
STDOUT is buffered by default and is the currently selected output file handle by default. You do not need the "select" in this case.
This should work fine...
#!/usr/bin/perl
use strict;
use warnings;
$|=1; # turns off stdout buffering
mysleep(10);
sub mysleep
{
my $seconds = shift;
print "Sleeping for $seconds seconds ... ";
for my $second (1..$seconds)
{
sleep(1);
print " $second";
}
print " done!\n";
}
I would not use "Sleep" as the subroutine name. Lower case "sleep" is the library's function name. This kind of upper vs lower case thing can lead to big and confusing troubles! I used "mysleep" instead of "Sleep".
PS: Something is very odd about your <code>...</code> tags. Do not enclose the <code>...</code> tags inside of something else.
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