Hi aplonis,

Sounds like this might be a case for coderefs:

my $foo = sub { print "Foo\n"; };
my $bar = sub { print "Bar\n"; };
my $x = $foo;
$x->();  # prints "Foo"
$x = $bar;
$x->();  # prints "Bar"

[download]

Or, perhaps the same with a dispatch table:

my %code = (
    foo => sub { print "Foo\n"; },
    bar => sub { print "Bar\n"; },
);
$code{foo}();  # prints "Foo"
$code{bar}();  # prints "Bar"

[download]

Update: Combining that with Corion's excellent post:

sub bar {
    my( $output ) = @_;
    $output->();
}
my $foo1 = sub { print "Foo\n"; };
my $foo2 = sub { print "Bar\n"; };
bar( $foo1 );  # prints "Foo"
bar( $foo2 );  # prints "Bar"

[download]

Hope this helps,
-- Hauke D

In reply to Re: Redefine the sub of a subref? by haukex
in thread Redefine the sub of a subref? by aplonis

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