Hello, I have a doubt which might seem basic but here it is: 

my $a = "This is Perl";
$a =~/^(.+)(e|r)(.*)$/;

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I get $1= This is Pe; $2= r; $3= l;

According to me, it should be "$1= This is Perl". $2 and $3 should be null. So my doubt is how are the capture brackets evaluated?

In reply to Basic Regular expression by skkeni04

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