Run this
and i bet it will become clearsub runDir($$) { my $prefix = shift @_; print '*'.$prefix,"\n"; my $dir = shift @_; print "**$dir*","\n"; opendir(DIR, $dir) or die $!; my @entries = readdir(DIR); # print @entries,"\n"; close(DIR); foreach my $file (@entries) { next if ($file =~ /^\.+$/); if ( -d $dir . '/' . $file) { print "***down runDir($prefix . $file . '_', $dir . '/' . +$file)\n"; runDir($prefix . $file . '_', $dir . '/' . $file); print "***up runDir($prefix . $file . '_', $dir . '/' . +$file)\n"; } elsif ( ( -f $dir . '/' . $file ) && ( $file =~ /\.config$/ +) && ($file !~ /^$prefix/)) { my $suffix = $file; $suffix =~ s/^(\S+)-.+\.config$/$1.config/; print "****rename $dir . '/' . $file, $dir . '/' . $prefix + . $suffix"."\n"; # rename $dir . '/' . $file, $dir . '/' . $prefix . $suffi +x ; } } }
In reply to Re: How to rename the files its directory structure using perl?
by huck
in thread How to rename the files its directory structure using perl?
by finddata
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