I have the project.txt files at following directory (/home/data/check_
+data).

project.txt contins following contents:
<code>
PROJECT {
NAME:DCMS_DEMO
BLOCKS:test,de_top,new_block2
DENY_USERS:
WELCOME:
REVISION_LOCATION:../setup/projects/DCMS_DEMO/project_space
CHECKLISTS:Synthesis_L2_checklist,Block_Physical_design_checklist,ICC_
+L2_Checklist,Overall_DV,Formality_DCT_Vs_ICC,Fullchip_Physical_design
+_checklist,Formality_RTL_Vs_DCT,synthesis,Timing_analysis_checklist,c
+hecklist_tmp,Power_analysis_checklist,Block_DV,DFT,ICC_Top_level_Chec
+klist,test_copy_checklist,ICC_DPMHV_Checklist,CAD_checklist,FrontEnd_
+Design_Checklist
DESCRIPTION:Demonstration project
OWNER:sanandak
ALLOWED_UNIX_GROUPS:
}

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Now i like to read the directory whereever the line starts with (REVISION_LOCATION:) from the project.txt files.And those directories should be consider as my input directory from the command line arguments.How can i do it. code which i had tried are as follows: 
#! /usr/bin/env perl
use strict;
use warnings;
use Getopt::Long   qw( GetOptions );
GetOptions(
    'root=s' => \my $input_dir,
    'outdir=s' => \my $output_dir,
    'file=s' => \my $mapfile,
)


In the above i called the directory straightly from the location but m
+y question is first i should read the project.txt file from one locat
+ion and  from that project.txt file i should read the directory(i.e t
+he line starts with REVISION_LOCATION).How can i script it using perl
+?

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In reply to How to read the input directory from command line arguments using perl? by finddata

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