A substitution regular expression normally changes the string to edit and returns the number of changes. Thus you actually changed your target string for your second case. To get what you meant to get, you would use the code 
#!/usr/bin/perl

use strict;
use warnings;


my $adate = "2017-01-29 11:30:07.370";
 
# more direct way, but returning a "1".
my $a_new_datetime = $adate;
$a_new_datetime =~ s/(\d{4})-(\d{2})-(\d{2})\s(\d{2}):(\d{2})(.*)/$2-$
+3-$1 $4:$5/;
print "\n 1 - $a_new_datetime\n\n";
  
my $new_datetime = $adate;
  
$new_datetime =~ s/(\d{4})-(\d{2})-(\d{2})\s(\d{2}):(\d{2})(.*)/$2-$3-
+$1 $4:$5/;
  
print " 2 - $new_datetime\n\n";

[download]
Alternatively, you can use the r modifier (s/_PATTERN_/_REPLACEMENT_/msixpodualngcer in perlop)to shift the behavior to return a value without editing the original string: 
#!/usr/bin/perl

use strict;
use warnings;


my $adate = "2017-01-29 11:30:07.370";
 
# more direct way, but returning a "1".
;
printf "\n 1 - %s\n\n", $adate =~ s/(\d{4})-(\d{2})-(\d{2})\s(\d{2}):(
+\d{2})(.*)/$2-$3-$1 $4:$5/r;
  
printf " 2 - %s\n\n", $adate =~ s/(\d{4})-(\d{2})-(\d{2})\s(\d{2}):(\d
+{2})(.*)/$2-$3-$1 $4:$5/r;

[download]

#11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.

In reply to Re: Assigning a parsed date to a variable by kennethk
in thread Assigning a parsed date to a variable by Anonymous Monk

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