Well, you can, but you just have to use an alternate syntax:

my $var = [foo()];

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In this case, you should know in advance that foo() returns a list that you want to take as an array reference. If a scalar is returned, it will automatically be populated as the first element in the array reference, regardless of its type.

In reply to Re: Reference to return value of a subroutine by stevieb
in thread Reference to return value of a subroutine by Christina

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