i had tried to print the output block in the perl cgi format which as follows.But nothing is printed for me.Let me know what mistake i had done in the following?
print "var data_run=[$row_array{$key}{'pend'}];\n"; print "var data_pend=[$row_array{$key}{'run'}];\n";

For my previous code which i used for questioning there i had printed which as follows.Here it works fine.which as follows
print "var data_running = [$var_data_running]; \n"; print "var data_pending = [$var_data_pending]; \n"; <br> Here the if and else statements variables are printed outside in perl +cgi format<br> <c> while(my @row_array=$sth->fetchrow_array) { if ($tmp == 0) { $var_data_running .= "\[\"$row_array[0] \($row_array[2]\)\",$r +ow_array[2]\]"; $var_data_pending .= "\[\"$row_array[0] \($row_array[1]\)\",$r +ow_array[1]\]"; $tmp++; } else { $var_data_running .= ",\[\"$row_array[0] \($row_array[2]\)\",$ +row_array[2]\]"; $var_data_pending .= ",\[\"$row_array[0] \($row_array[1]\)\",$ +row_array[1]\]"; } }
</c>
Likewise the above if and else statement variables i had tried to print the same varibales for the code which you mentioned but i had failes in those cases.
Thanks for any help.

In reply to Re^4: How to add columns with new row name using perl from mysql query? by finddata
in thread How to add columns with new row name using perl from mysql query? by perlanswers

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