Instead of around ['do_something','do_otherthing'] => sub { ... }, try this, as suggested by Moose::Manual::MethodModifiers:

for my $method ('do_something','do_otherthing') {
    around $method => sub {
        my $orig = shift;
        my $self = shift;
        print "around $method\n";
        if ($method eq 'do_something') { ... }
        $self->$orig(@_);
    };
}

[download]

Update 2: $orig and \&do_something are giving different code refs ... Could someone explain me why this happens?

By the time the piece of code "\&do_something" is executed, do_something is already pointing to the wrapped sub do_something.

{
    package Bar;
    use Moose;
    sub do_something { print "did something\n" }
    my $before = \&do_something;
    around 'do_something' => sub {
        my $orig = shift;
        my $self = shift;
        print "around do_something\n";
        print "\t\$orig=$orig\n";
        print "\t\$before=$before\n";
        print "\t\\&do_something=".\&do_something."\n";
    };
}
my $bar = Bar->new;
$bar->do_something;
print "can=", $bar->can('do_something'), "\n";
__END__
around do_something
    $orig=CODE(0x223d5e8)
    $before=CODE(0x223d5e8)
    \&do_something=CODE(0x228ae92)
can=CODE(0x228ae92)

[download]

Update 3: A bit more explanation: Notice how $before holds the reference to the original sub do_something before it's wrapped by around, and ->can('do_something') reports the coderef of the final, wrapped method. Compare these two to $orig and \&do_something. Remember that the anonymous sub given to around doesn't get executed until the method is called, by which time it's already been wrapped, at which time \&do_something points to the wrapped method.

Update 1: In my very first code example, added an example of checking which method is being wrapped.

In reply to Re: Code ref inside around modifier (updated) by haukex
in thread Code ref inside around modifier by #perl_noob

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