Surely order by data1+data2 gives the same top 5 names just sorted differently whereas if you do separate queries the top 5 names might be different. To do both in 1 query I guess you could do something complicated like this 

#!perl
use strict; 
use DBI; 

my $DBH; my $data1; my $data2;
datas('dbname');
print "$data1\n$data2";

sub datas
{
  $data1 = "";
  $data2 = "";
  my $str = shift;
  $DBH = &connect or die "Cannot connect to the sql server \n";
  $DBH->do("USE $str;");
  my $stmt="
( select name,data1
  from datas 
  order by data1 desc 
  limit 5 )

union all
( select 'added' ,sum(data1) 
  from (
    select data1
    from datas 
    order by data1 desc 
    limit  18446744073709551615 offset 5
  ) t1
)

union all
( select name,data2
  from datas 
  order by data2 desc 
  limit 5 )

union all
( select 'added' ,sum(data2) 
  from (
    select data2
    from datas 
    order by data2 desc 
    limit  18446744073709551615 offset 5
  ) t1
)";
    
  my $sth = $DBH->prepare( $stmt );
  $sth->execute() or die $sth->errstr;
    
  my $tmp = 0;
  while(my @row_array=$sth->fetchrow_array)
  {
    if ($tmp > 5){
      if ($tmp == 6 ) {
        $data2 = "\[\"$row_array[0] \($row_array[1]\)\",$row_array[1]\
+]";
      }
      else {
        $data2 .= ",\[\"$row_array[0] \($row_array[1]\)\",$row_array[1
+]\]";
      }
    } else {
       if ($tmp == 0 ) {
         $data1 = "\[\"$row_array[0] \($row_array[1]\)\",$row_array[1]
+\]";
       }
       else {
         $data1 .= ",\[\"$row_array[0] \($row_array[1]\)\",$row_array[
+1]\]";
       }  
    }
    ++$tmp;
  }
  $sth->finish;
  $DBH->disconnect();
}

[download]
poj

In reply to Re^5: perl sql to separate and sort the column separately? by poj
in thread perl sql to separate and sort the column separately? by gpssana

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