Actually the scalar in the first case isn't necessary since boolean context is (more or less) scalar context as is shown with the code below. 

@a = ();
print "try 1\n";
print "Has elements\n" if @a;

push @a, 1;
print "try 2\n";
print "Has elements\n" if @a;

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In reply to Re: Re: What does $# stand for? by Fletch
in thread What does $# stand for? by Kiko

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