Just another set of examples to drive home the point that, whatever else may happen (i.e., with the newlines), the  * (asterisk) is always gone:

c:\@Work\Perl\monks>perl -wMstrict -le "my $s = qq{AAA*\n}; ;; my $t = $s; print qq{A1: '$t'}; $t =~ s/\*$//; print qq{A2: '$t'}; ;; $t = $s; print qq{B1: '$t'}; $t =~ s/\*\s$//; print qq{B2: '$t'}; ;; $t = $s; print qq{C1: '$t'}; $t =~ s/\*[\n]$//; print qq{C2: '$t'}; " A1: 'AAA* ' A2: 'AAA ' B1: 'AAA* ' B2: 'AAA' C1: 'AAA* ' C2: 'AAA'
Note that:  \n is a member of the  \s (whitespace) set;  [\n] is the same as  \n (newline) alone. Please see perlre, perlretut, and perlrequick.

Update:

Does perl let you print $line as a literal string with \n etc.?
Some questions can be answered by simple experimentation. What happens when you print the strings "foobar", "foo\nbar", "foo\n\n\nbar", "foobar\n", "foobar\n\n\n", etc?


Give a man a fish:  <%-{-{-{-<


In reply to Re: Removing trailing asterisk from lines with regex by AnomalousMonk
in thread Removing trailing asterisk from lines with regex by Tmms

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